In a 3-phase star connected system, the line-to-line voltages can be calculated using the formula:

Vline-to-line = √3 * Vphase * ∠(phase angle ± 30°)

Given that VYN = 100∠−120° V and VBN = 100∠120° V, we can calculate VYB as follows:

First, we need to convert the phase voltages to rectangular form:

VYN = 100∠−120° = 50 - 86.6j
VBN = 100∠120° = -50 - 86.6j

Then, we subtract VBN from VYN to get VYB:

VYB = VYN - VBN = (50 - 86.6j) - (-50 - 86.6j) = 100

So, VYB = 100 V. This doesn't match any of the given options, so there might be a mistake in the question or the given options.

Question

In a 3-phase star connected system, the line-to-line voltages can be calculated using the formula:

Vline-to-line = √3 * Vphase * ∠(phase angle ± 30°)

Given that VYN = 100∠−120° V and VBN = 100∠120° V, we can calculate VYB as follows:

First, we need to convert the phase voltages to rectangular form:

VYN = 100∠−120° = 50 - 86.6j
VBN = 100∠120° = -50 - 86.6j

Then, we subtract VBN from VYN to get VYB:

VYB = VYN - VBN = (50 - 86.6j) - (-50 - 86.6j) = 100

So, VYB = 100 V. This doesn't match any of the given options, so there might be a mistake in the question or the given options.

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