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In a certain code language, if BUG = 90 and ALMS = 180, then CADET = ?153165175148

Question

In a certain code language, if BUG = 90 and ALMS = 180, then CADET = ?153165175148

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Solution

The question seems to be a type of coding-decoding problem often found in reasoning sections of various competitive exams.

Let's try to decode the logic behind the given codes:

  1. BUG = 90
  2. ALMS = 180

If we look at the alphabets and their corresponding positions in the English language:

B is 2nd, U is 21st, and G is 7th. If we add these positions together, we get 2 + 21 + 7 = 30. But in the code, BUG is represented as 90, which is 30 * 3.

Similarly, for ALMS, A is 1st, L is 12th, M is 13th, and S is 19th. Adding these together, we get 1 + 12 + 13 + 19 = 45. In the code, ALMS is represented as 180, which is 45 * 4.

From these observations, it seems that the code for a word is the sum of the positions of its letters in the alphabet, multiplied by the number of letters in the word.

So, for CADET, C is 3rd, A is 1st, D is 4th, E is 5th, and T is 20th. Adding these together, we get 3 + 1 + 4 + 5 + 20 = 33.

CADET has 5 letters, so the final code would be 33 * 5 = 165.

So, CADET = 165 in this code language.

This problem has been solved

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