Select the correct answerWhat will be the output of the following Java code? class Name { public static void main(String args[]) { try { int ct1 = 0; int ct2 = 5; int ct3 = ct1 / ct2; System.out.print("Hello"); } catch(Exception e) { System.out.print("Codetantra"); } } }OptionsCodetantraHelloHelloCodetantraCompilation Error
Question
Select the correct answerWhat will be the output of the following Java code? class Name { public static void main(String args[]) { try { int ct1 = 0; int ct2 = 5; int ct3 = ct1 / ct2; System.out.print("Hello"); } catch(Exception e) { System.out.print("Codetantra"); } } }OptionsCodetantraHelloHelloCodetantraCompilation Error
Solution
The correct answer is "Hello".
Here's the step by step explanation:
- The code starts with the declaration of a class named "Name".
- Inside this class, there is a main method which is the entry point of any Java application.
- Inside the main method, a try-catch block is used. This is used to handle exceptions in Java.
- Inside the try block, three integer variables ct1, ct2, and ct3 are declared and initialized. ct1 is initialized to 0, ct2 is initialized to 5, and ct3 is the result of ct1 divided by ct2. Since ct1 is 0 and ct2 is 5, the result of the division is 0. This operation does not throw any exception.
- After the division, the code prints "Hello" to the console.
- Since no exception is thrown in the try block, the catch block is not executed. Therefore, "Codetantra" is not printed to the console.
- So, the output of the code is "Hello".
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