In the mass spectrum of pentane, the presence of a peak at m/z = 57 is most likely due to the loss of what radical from the molecule?Select answer from the options belowpropyl radicalmethyl radicalethyl radicalbutyl radical
Question
In the mass spectrum of pentane, the presence of a peak at m/z = 57 is most likely due to the loss of what radical from the molecule?Select answer from the options belowpropyl radicalmethyl radicalethyl radicalbutyl radical
Solution
The peak at m/z = 57 in the mass spectrum of pentane is most likely due to the loss of a methyl radical.
Here's the step-by-step reasoning:
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The molecular weight of pentane (C5H12) is 72.
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If we see a peak at m/z = 57, this suggests that a fragment of the original molecule (pentane) has been lost.
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The difference between the molecular weight of pentane and the m/z value is 72 - 57 = 15.
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The molecular weight of a methyl radical (CH3) is 15.
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Therefore, the loss of a methyl radical from the pentane molecule would result in a fragment with a m/z value of 57.
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