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There are five tanks of 500 ml each. In five tanks 1, 2, 3, 4 and 5, there are five different chemicals (liquid) which are to be mixed.There are four outlets from each tank to the other four tanks.The flow of liquid through each outlet is as followstank 1 is 20 litre/mintank 2 is 30 litre/mintank 3 is 25 litre/mintank 4 is 12 litre/mintank 5 is 48 litre/min.Which tank empties first? (Assume all tanks are opened simulteneously)

Question

There are five tanks of 500 ml each. In five tanks 1, 2, 3, 4 and 5, there are five different chemicals (liquid) which are to be mixed.There are four outlets from each tank to the other four tanks.The flow of liquid through each outlet is as followstank 1 is 20 litre/mintank 2 is 30 litre/mintank 3 is 25 litre/mintank 4 is 12 litre/mintank 5 is 48 litre/min.Which tank empties first? (Assume all tanks are opened simulteneously)

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Solution

The problem can be solved by calculating the time it takes for each tank to empty.

The volume of each tank is 500 ml, which is equal to 0.5 liters.

The flow rate from each tank is given in liters per minute.

So, the time it takes for each tank to empty is the volume of the tank divided by the flow rate from the tank.

For tank 1, the time is 0.5 liters / 20 liters per minute = 0.025 minutes.

For tank 2, the time is 0.5 liters / 30 liters per minute = 0.0167 minutes.

For tank 3, the time is 0.5 liters / 25 liters per minute = 0.02 minutes.

For tank 4, the time is 0.5 liters / 12 liters per minute = 0.0417 minutes.

For tank 5, the time is 0.5 liters / 48 liters per minute = 0.0104 minutes.

So, tank 5 empties first.

This problem has been solved

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