A bike going round a circular track whose radius is 63 m experiences an acceleration of 2.3 m/s^2. What is its velocity?
Question
A bike going round a circular track whose radius is 63 m experiences an acceleration of 2.3 m/s^2. What is its velocity?
Solution 1
To find the velocity of the bike, we can use the formula for centripetal acceleration, which is a = v^2 / r, where a is the acceleration, v is the velocity, and r is the radius of the circular path.
Given that the acceleration a is 2.3 m/s^2 and the radius r is 63 m, we can rearrange the formula to solve for v:
v = sqrt(a * r)
Substituting the given values:
v = sqrt(2.3 m/s^2 * 63 m)
v = sqrt(144.9 m^2/s^2)
v = 12.04 m/s
So, the velocity of the bike is approximately 12.04 m/s.
Solution 2
The velocity of the bike can be calculated using the formula for centripetal acceleration, which is a = v^2 / r, where a is the acceleration, v is the velocity, and r is the radius of the circular path.
Given that the acceleration a is 2.3 m/s^2 and the radius r is 63 m, we can rearrange the formula to solve for v:
v = sqrt(a * r)
Substituting the given values:
v = sqrt(2.3 m/s^2 * 63 m)
v = sqrt(144.9 m^2/s^2)
v = 12.04 m/s
So, the velocity of the bike is approximately 12.04 m/s.
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