Question 1: Assuming there is a list of integers, create a new list where each element is the square of the corresponding element in the original list. numbers = [1, 2, 3, 4, 5]
Question
Question 1: Assuming there is a list of integers, create a new list where each element is the square of the corresponding element in the original list. numbers = [1, 2, 3, 4, 5]
Solution
Here is a step-by-step solution in Python:
Step 1: First, we define the original list of integers:
numbers = [1, 2, 3, 4, 5]
Step 2: Next, we create a new list using list comprehension. This is a Pythonic way to create lists based on existing lists. Here, we square each number in the original list:
squared_numbers = [number ** 2 for number in numbers]
Step 3: Finally, we print the new list to check the result:
print(squared_numbers)
When you run this code, it will output:
[1, 4, 9, 16, 25]
This means that each number in the original list has been squared in the new list.
Similar Questions
Square of a NumberYou are given a Python code snippet that aims to demonstrate list comprehension to create a new list of squared numbers from a given list of integers. However, some parts of the code are missing. Fill in the missing code to complete the program.Sample Test CasesTest Case 1:Expected Output:Enter·a·list·of·integers·separated·by·commas:·1,2,3,4New·list·of·squared·numbers:·[1,·4,·9,·16]Submit1234567891011121314#·Fill·in·the·missing·code·below·to·demonstrate·list·comprehension¬¬#·Prompt·the·user·to·enter·a·list·of·integers·separated·by·commas¬numbers·=·input("Enter·a·list·of·integers·separated·by·commas:·").split(',')¬¬#·Convert·the·input·strings·to·integers¬numbers·=·[int(num)·for·num·in·numbers]¬¬#·Fill·in·the·missing·code·to·create·a·new·list·of·squared·numbers·using·list·comprehension¬squared_numbers·=·[·············]¬¬#·Display·the·new·list·of·squared·numbers¬print("New·list·of·squared·numbers:",··)¬¶
python code to square every num in the list
I have a list sample_data = [1,2,3,4,5,6,7,8,9,10], and I want [1,4,9,16,25,36,49,64,81,100] from it. What should be the possible solution?Select one:square(sample_data)sq(sample_data)sample_data.squaredsqaure(sample_data)
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