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Which of the following is true for a universe without dark energy and with positive total energy?The recommended time to answer this question is 2.5 minutes.Soru 9YanıtThe potential energy of such a universe is more dominant than its kinetic energy.The curvature parameter of such a universe is k=0.Such a universe is called a closed universe.Such a universe starts with the big bang, expands for a while, and then contracts again.A two-dimensional representation of such a universe is like a saddle.

Question

Which of the following is true for a universe without dark energy and with positive total energy?The recommended time to answer this question is 2.5 minutes.Soru 9YanıtThe potential energy of such a universe is more dominant than its kinetic energy.The curvature parameter of such a universe is k=0.Such a universe is called a closed universe.Such a universe starts with the big bang, expands for a while, and then contracts again.A two-dimensional representation of such a universe is like a saddle.

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Solution

The correct statement for a universe without dark energy and with positive total energy is: "Such a universe starts with the big bang, expands for a while, and then contracts again."

This is because in a universe with positive total energy and no dark energy, the gravitational pull of matter eventually slows down the expansion started by the Big Bang and pulls everything back together in a "Big Crunch".

The other statements are incorrect because:

  • The potential energy of such a universe is not necessarily more dominant than its kinetic energy. It depends on the specific conditions of the universe.
  • The curvature parameter of such a universe is not necessarily k=0. A positive total energy implies a positive curvature (k=1), which corresponds to a closed universe.
  • Such a universe is indeed called a closed universe, but this is not exclusive to universes without dark energy.
  • A two-dimensional representation of such a universe is not like a saddle. A saddle-shaped universe corresponds to a negative curvature (k=-1), which is not the case here.

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