To solve this problem, we can use a system of linear equations. Let's denote the cost of an advance ticket as 'a' and the cost of a same-day ticket as 's'.

From the problem, we know two things:

1. The combined cost of one advance ticket and one same-day ticket is $50. This can be written as: a + s = 50
2. For one performance, 25 advance tickets and 15 same-day tickets were sold for a total of $900. This can be written as: 25a + 15s = 900

Now we have a system of two equations, and we can solve it step by step.

Step 1: Solve the first equation for 'a': a = 50 - s

Step 2: Substitute 'a' from the first equation into the second equation: 25(50 - s) + 15s = 900

Step 3: Simplify the equation: 1250 - 25s + 15s = 900

Step 4: Combine like terms: -10s = -350

Step 5: Solve for 's': s = 35

Step 6: Substitute 's' = 35 into the first equation: a + 35 = 50

Step 7: Solve for 'a': a = 15

So, the cost of an advance ticket is $15 and the cost of a same-day ticket is $35.

Question

To solve this problem, we can use a system of linear equations. Let's denote the cost of an advance ticket as 'a' and the cost of a same-day ticket as 's'.

From the problem, we know two things:

1. The combined cost of one advance ticket and one same-day ticket is $50. This can be written as: a + s = 50
2. For one performance, 25 advance tickets and 15 same-day tickets were sold for a total of $900. This can be written as: 25a + 15s = 900

Now we have a system of two equations, and we can solve it step by step.

Step 1: Solve the first equation for 'a': a = 50 - s

Step 2: Substitute 'a' from the first equation into the second equation: 25(50 - s) + 15s = 900

Step 3: Simplify the equation: 1250 - 25s + 15s = 900

Step 4: Combine like terms: -10s = -350

Step 5: Solve for 's': s = 35

Step 6: Substitute 's' = 35 into the first equation: a + 35 = 50

Step 7: Solve for 'a': a = 15

So, the cost of an advance ticket is $15 and the cost of a same-day ticket is $35.

Knowee AI · Accepted Answer