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Rank these single bonds in order of least to greatest strength based on differences in electronegativity:H-C, H-O, H-F, H-NGroup of answer choicesH-C, H-O, H-F, H-NH-O, H-F, H-N, H-CH-F, H-N, H-C, H-OH-N, H-O, H-F, H-CH-C, H-O, H-N, H-FH-N, H-O, H-C, H-FH-C, H-N, H-O, H-F

Question

Rank these single bonds in order of least to greatest strength based on differences in electronegativity:H-C, H-O, H-F, H-NGroup of answer choicesH-C, H-O, H-F, H-NH-O, H-F, H-N, H-CH-F, H-N, H-C, H-OH-N, H-O, H-F, H-CH-C, H-O, H-N, H-FH-N, H-O, H-C, H-FH-C, H-N, H-O, H-F

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Solution

The strength of a single bond is directly related to the difference in electronegativity between the two atoms. The greater the difference in electronegativity, the stronger the bond.

Here are the electronegativity values for the atoms in question:

  • Hydrogen (H): 2.20
  • Carbon (C): 2.55
  • Oxygen (O): 3.44
  • Nitrogen (N): 3.04
  • Fluorine (F): 3.98

Now, let's calculate the difference in electronegativity for each bond:

  • H-C: |2.20 - 2.55| = 0.35
  • H-O: |2.20 - 3.44| = 1.24
  • H-F: |2.20 - 3.98| = 1.78
  • H-N: |2.20 - 3.04| = 0.84

So, the order of bond strength from least to greatest based on differences in electronegativity is:

H-C, H-N, H-O, H-F

This problem has been solved

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