write a c perform A-B and B-A where A=F A C 9) base 16 and B=( C A D) base 16 using 16's compliment

Sure, here is a simple C program that performs the operations A-B and B-A using 16's complement.

#include<stdio.h>
#include<math.h>

// Function to find the 16's complement
int findComplement(int num) {
    int bit_count = log2(num) + 1;
    int mask = (1 << bit_count) - 1;
    return mask ^ num;
}

int main() {
    // Convert hexadecimal to decimal
    int A = 0xFAC9;
    int B = 0xCAD;

    // Find 16's complement of B
    int B_complement = findComplement(B);

    // Perform A - B
    int A_minus_B = A + B_complement + 1;

    // Find 16's complement of A
    int A_complement = findComplement(A);

    // Perform B - A
    int B_minus_A = B + A_complement + 1;

    printf("A - B = %X\n", A_minus_B);
    printf("B - A = %X\n", B_minus_A);

    return 0;
}

This program first converts the hexadecimal numbers to decimal. Then it finds the 16's complement of B and adds it to A to perform A - B. Similarly, it finds the 16's complement of A and adds it to B to perform B - A. The results are then printed in hexadecimal format.