The mass of the solid cylinder is 1000 gram and its diameter is 20 cm. What is the moment of inertia when the solid cylinder rotates with its own axis? assigment problem
Question
The mass of the solid cylinder is 1000 gram and its diameter is 20 cm. What is the moment of inertia when the solid cylinder rotates with its own axis? assigment problem
Solution
The moment of inertia (I) of a solid cylinder rotating about its own axis can be calculated using the formula:
I = 0.5 * m * r^2
where: m is the mass of the cylinder, and r is the radius of the cylinder.
Given that the mass (m) of the cylinder is 1000 grams (or 1 kg, since 1 kg = 1000 grams), and the diameter of the cylinder is 20 cm (or 0.2 m, since 1 m = 100 cm), we can calculate the radius (r) as half of the diameter, which is 0.1 m.
Substituting these values into the formula, we get:
I = 0.5 * 1 kg * (0.1 m)^2 I = 0.5 * 1 kg * 0.01 m^2 I = 0.005 kg*m^2
So, the moment of inertia of the solid cylinder when it rotates about its own axis is 0.005 kg*m^2.
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