A 2-lips twist drill having a diameter of 4 [mm] and point angle 117 rotates at 691 [RPM] and feeds towards the work part at a rate of 0.38 [mm/rev], to drill a through hole of 34 depth. Machining allowance is 4 [mm]. Ignore length of chesil. MRR in [mm3/min] is then given by
Question
A 2-lips twist drill having a diameter of 4 [mm] and point angle 117 rotates at 691 [RPM] and feeds towards the work part at a rate of 0.38 [mm/rev], to drill a through hole of 34 depth. Machining allowance is 4 [mm]. Ignore length of chesil. MRR in [mm3/min] is then given by
Solution
The Material Removal Rate (MRR) in drilling can be calculated using the formula:
MRR = π * D * f * N
where:
- D is the diameter of the drill (in mm)
- f is the feed rate (in mm/rev)
- N is the rotational speed (in RPM)
Given:
- D = 4 mm
- f = 0.38 mm/rev
- N = 691 RPM
Substituting these values into the formula, we get:
MRR = π * 4 * 0.38 * 691
Calculating this gives:
MRR = 3265.68 mm³/min
So, the Material Removal Rate is 3265.68 mm³/min.
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