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A model rocket with a mass of 750 grams is launched straight up. It achieves a speed of 25.0 m/s in 2.00 seconds. Ignoring any change in mass of the rocket due to expelled fuel, and neglecting air resistance, the magnitude of the average net force on the rocket is

Question

A model rocket with a mass of 750 grams is launched straight up. It achieves a speed of 25.0 m/s in 2.00 seconds. Ignoring any change in mass of the rocket due to expelled fuel, and neglecting air resistance, the magnitude of the average net force on the rocket is

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Solution

To find the average net force on the rocket, we can use Newton's second law of motion, which states that the force acting on an object is equal to its mass times its acceleration (F = ma).

First, we need to find the acceleration of the rocket. Acceleration is the change in velocity over time. In this case, the rocket goes from a speed of 0 m/s to 25.0 m/s in 2.00 seconds. So, the acceleration (a) can be calculated as:

a = Δv / t a = (25.0 m/s - 0 m/s) / 2.00 s a = 12.5 m/s²

Next, we need to convert the mass of the rocket from grams to kilograms, because in the International System of Units (SI), the unit of mass is the kilogram.

m = 750 g = 0.750 kg

Now we can calculate the force (F):

F = ma F = 0.750 kg * 12.5 m/s² F = 9.375 N

So, the magnitude of the average net force on the rocket is 9.375 Newtons.

This problem has been solved

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