Consider the following equation representing an oxidation reduction reaction: Zn(s) + CuSO4(aq) →→ ZnSO4(aq) + Cu(s), Which statement is true about this reaction?Question 21Answera.Cu is oxidizedb.Oxygen is reducedc.Zn is oxidizedd.S is reduced
Question
Consider the following equation representing an oxidation reduction reaction: Zn(s) + CuSO4(aq) →→ ZnSO4(aq) + Cu(s), Which statement is true about this reaction?Question 21Answera.Cu is oxidizedb.Oxygen is reducedc.Zn is oxidizedd.S is reduced
Solution
In the given reaction: Zn(s) + CuSO4(aq) → ZnSO4(aq) + Cu(s), zinc (Zn) is oxidized.
Here's why:
In a redox (oxidation-reduction) reaction, one species is oxidized (loses electrons) and another species is reduced (gains electrons).
In this reaction, zinc starts as a neutral atom (Zn) and ends up in a compound (ZnSO4) where it has a charge of +2. This means it has lost two electrons, so it has been oxidized.
Copper (Cu), on the other hand, starts in a compound (CuSO4) where it has a charge of +2 and ends up as a neutral atom (Cu), meaning it has gained two electrons and has been reduced.
So, the correct answer is c. Zn is oxidized.
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