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If demand is given by qd = 20 – P and supply is given by qs = P, then producer surplus is: a. 50 b. 100 c. 30 d. 20

Question

If demand is given by qd = 20 – P and supply is given by qs = P, then producer surplus is:

a. 50

b. 100

c. 30

d. 20

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Solution

First, we need to find the equilibrium price and quantity. This is where quantity demanded (qd) equals quantity supplied (qs).

Setting qd = qs, we get:

20 - P = P

Solving for P, we get:

P = 20/2 = 10

Substituting P = 10 into the supply equation, we get:

qs = 10

Now, we can calculate the producer surplus. Producer surplus is the area above the supply curve and below the price, up to the quantity sold. In this case, it's a triangle with a base of 10 (the quantity) and a height of 10 (the price minus the minimum price, which is 0 in this case).

The area of a triangle is 0.5 * base * height, so the producer surplus is:

0.5 * 10 * 10 = 50

So, the correct answer is:

a. 50

This problem has been solved

Similar Questions

To find the consumer surplus given the demand function \( P = \frac{100}{Q + 2} \) and the market price \( P = 20 \), follow these steps: 1. **Find the quantity \( Q \) at the market price \( P = 20 \)**: \[ 20 = \frac{100}{Q + 2} \] Solve for \( Q \): \[ 20(Q + 2) = 100 \] \[ 20Q + 40 = 100 \] \[ 20Q = 60 \] \[ Q = 3 \] 2. **Set up the integral for consumer surplus**: Consumer surplus is the area between the demand curve and the market price, from \( Q = 0 \) to \( Q = 3 \): \[ \text{Consumer Surplus} = \int_0^3 \left( \frac{100}{Q + 2} - 20 \right) \, dQ \] 3. **Evaluate the integral**: \[ \int_0^3 \left( \frac{100}{Q + 2} - 20 \right) \, dQ = \int_0^3 \frac{100}{Q + 2} \, dQ - \int_0^3 20 \, dQ \] 4. **Find the antiderivatives**: \[ \int \frac{100}{Q + 2} \, dQ = 100 \ln|Q + 2| + C \] \[ \int 20 \, dQ = 20Q + C \] 5. **Apply the limits of integration**: \[ \left[ 100 \ln|Q + 2| \right]_0^3 - \left[ 20Q \right]_0^3 \] 6. **Evaluate the definite integrals**: \[ \left[ 100 \ln|Q + 2| \right]_0^3 = 100 \ln(5) - 100 \ln(2) \] \[ \left[ 20Q \right]_0^3 = 20(3) - 20(0) = 60 \] 7. **Combine the results**: \[ 100 \ln(5) - 100 \ln(2) - 60 \] \[ 100 (\ln(5) - \ln(2)) - 60 \] \[ 100 \ln\left(\frac{5}{2}\right) - 60 \] 8. **Calculate the numerical value**: \[ 100 \ln\left(\frac{5}{2}\right) - 60 \approx 100 \times 0.9163 - 60 \approx 91.63 - 60 \approx 31.63 \] So, the consumer surplus is approximately \( 31.6291 \). The correct answer is: - \( 31.6291 \)

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