To calculate the number of address lines needed for a 2 Mbyte address range, you need to understand that 1 byte is equal to 8 bits. Therefore, 2 Mbytes is equal to 2 * 1024 * 1024 bytes = 2097152 bytes.

The number of address lines needed is the number of bits required to uniquely identify each byte in the address range. This is calculated by taking the base-2 logarithm of the number of bytes.

So, the number of address lines needed is log2(2097152) = 21.

Therefore, 21 address lines are needed for a 2 Mbyte address range.

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To calculate the number of address lines needed for a 2 Mbyte address range, you need to understand that 1 byte is equal to 8 bits. Therefore, 2 Mbytes is equal to 2 * 1024 * 1024 bytes = 2097152 bytes.

The number of address lines needed is the number of bits required to uniquely identify each byte in the address range. This is calculated by taking the base-2 logarithm of the number of bytes.

So, the number of address lines needed is log2(2097152) = 21.

Therefore, 21 address lines are needed for a 2 Mbyte address range.

Knowee AI · Accepted Answer

To calculate the number of address lines needed for a 2 Mbyte address range, you need to understand that 1 byte is equal to 8 bits. Therefore, 2 Mbytes is equal to 2 * 1024 * 1024 bytes = 2097152 bytes.

The number of address lines needed is the number of bits required to uniquely identify each byte in the address range. This is calculated by taking the base-2 logarithm of the number of bytes.

So, the number of address lines needed is log2(2097152) = 21.

Therefore, 21 address lines are needed for a 2 Mbyte address range.

How many address lines are needed for a 2 Mbyte address range?

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