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The intersection of lines l and m forms the 4 angles ∠𝐴, ∠𝐵, ∠𝐶 𝑎𝑛𝑑  ∠𝐷, and . The measure of ∠𝐵  is  312 times the measure of ∠𝐴 . Which of the following values is closest to the measure of ∠𝐴 ?

Question

The intersection of lines l and m forms the 4 angles ∠𝐴, ∠𝐵, ∠𝐶 𝑎𝑛𝑑  ∠𝐷, and . The measure of ∠𝐵  is  312 times the measure of ∠𝐴 . Which of the following values is closest to the measure of ∠𝐴 ?

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Solution 1

Given that the measure of ∠B is 312 times the measure of ∠A, we can express this relationship as ∠B = 312∠A.

We also know that when two lines intersect, they form four angles. The opposite angles are equal and the sum of adjacent angles is 180 degrees.

So, ∠A = ∠C and ∠B = ∠D. Also, ∠A + ∠B = 180 degrees.

Substituting ∠B = 312∠A into the equation ∠A + ∠B = 180, we get ∠A + 312∠A = 180.

Solving this equation for ∠A, we get 313∠A = 180, so ∠A = 180/313 ≈ 0.575.

Therefore, the measure of ∠A is approximately 0.575 degrees.

This problem has been solved

Solution 2

To solve this problem, we need to understand that when two lines intersect, they form four angles. The angles opposite each other (known as vertical angles) are equal. So, ∠A = ∠C and ∠B = ∠D.

Given that ∠B is 312 times the measure of ∠A, we can say that ∠B = 312∠A.

Since ∠B = ∠D, we can also say that ∠D = 312∠A.

Now, the sum of all angles at a point is 360 degrees. So, ∠A + ∠B + ∠C + ∠D = 360 degrees.

Substituting the values we have:

∠A + 312∠A + ∠A + 312∠A = 360

This simplifies to 626∠A = 360

So, ∠A = 360/626 = 0.575 degrees, which is the closest measure of ∠A.

This problem has been solved

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