The population of a town increases by 10% every year. If the population at the end of three years is 2,66,200. Then the population at the start of the first year is?Question 1Answera.230000b.220000c.200000d.240000

The problem states that the population of a town increases by 10% every year and that the population at the end of three years is 2,66,200. We are asked to find the population at the start of the first year.

Let's denote the population at the start of the first year as P.

According to the problem, the population increases by 10% every year. This means that at the end of the first year, the population is P * (1 + 10/100) = P * 1.1.

At the end of the second year, the population is P * 1.1 * 1.1 = P * 1.21.

At the end of the third year, the population is P * 1.21 * 1.1 = P * 1.331.

We know that this population is 2,66,200. Therefore, we can set up the equation P * 1.331 = 2,66,200.

To solve for P, we divide both sides of the equation by 1.331:

P = 2,66,200 / 1.331 ≈ 200,000.

So, the population at the start of the first year was approximately 200,000.

Therefore, the correct answer is c. 200,000.