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Create a list num=[23,12,5,9,65,44].➢ Print the length of the list.➢ Print the elements from second to fourth position using positive indexing.➢ Print the elements from position third to fifth using negative indexing

Question

Create a list num=[23,12,5,9,65,44].➢ Print the length of the list.➢ Print the elements from second to fourth position using positive indexing.➢ Print the elements from position third to fifth using negative indexing

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Solution 1

Sure, here is the Python code for your request:

# Create a list
num = [23, 12, 5, 9, 65, 44]

# Print the length of the list
print("Length of the list: ", len(num))

# Print the elements from second to fourth position using positive indexing
print("Elements from second to fourth position: ", num[1:4])

# Print the elements from position third to fifth using negative indexing
print("Elements from third to fifth position: ", num[-4:-1])

Here is the explanation:

  1. We first create a list named num with the elements you provided.
  2. We then print the length of the list using the len() function.
  3. To print the elements from the second to the fourth position, we use positive indexing. In Python, indexing starts from 0, so the second element is at index 1 and the fourth element is at index 3. We use slicing (num[1:4]) to get the elements. The end index in a slice is exclusive, so we need to add 1 to it.
  4. To print the elements from the third to the fifth position using negative indexing, we use num[-4:-1]. In Python, negative indexing starts from -1 (which refers to the last element). So, the third element from the end is at index -4 and the fifth element from the end is at index -2. We add 1 to the end index because slicing is end-exclusive.

This problem has been solved

Solution 2

Sure, here are the steps to perform the operations you asked for in Python:

  1. Create a list:
num = [23,12,5,9,65,44]
  1. Print the length of the list:
print(len(num))

This will output: 6

  1. Print the elements from second to fourth position using positive indexing:
print(num[1:4])

This will output: [12, 5, 9]

  1. Print the elements from position third to fifth using negative indexing:
print(num[-4:-1])

This will output: [5, 9, 65]

Remember, Python uses zero-based indexing, so the first element is at position 0. Also, in slicing, the end index is exclusive, which means it doesn't include the element at the end index.

This problem has been solved

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