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Pick the odd one out.Question 4Select one:๐œ†ย is a solution of the characteristic equation ๐‘‘๐‘’๐‘กย (๐œ†๐ผย -ย ๐ด)ย =ย 0.๐œ† is an eigen value of A.There is a nonzero vector x such that ๐ด๐‘ฅย =ย ๐œ†๐‘ฅ.The system of equations (๐œ†๐ผย -ย ๐ด)๐‘ฅย =ย 0ย has trivial solutions.

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Pick the odd one out.Question 4Select one:๐œ†ย is a solution of the characteristic equation ๐‘‘๐‘’๐‘กย (๐œ†๐ผย -ย ๐ด)ย =ย 0.๐œ† is an eigen value of A.There is a nonzero vector x such that ๐ด๐‘ฅย =ย ๐œ†๐‘ฅ.The system of equations (๐œ†๐ผย -ย ๐ด)๐‘ฅย =ย 0ย has trivial solutions.

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Solution

The odd one out is "The system of equations (๐œ†๐ผ - ๐ด)๐‘ฅ = 0 has trivial solutions."

The reason is that for a value ๐œ† to be an eigenvalue of a matrix A, the system of equations (๐œ†๐ผ - ๐ด)๐‘ฅ = 0 must have nontrivial solutions. This is because the definition of an eigenvalue is a scalar ๐œ† such that when it is subtracted from the diagonal elements of A (forming ๐œ†๐ผ - ๐ด) and multiplied by a vector x, the result is the zero vector, but x itself is not the zero vector (i.e., it is a nontrivial solution). The other three statements are all consistent with the definition of an eigenvalue.

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