Directions: Sania walks 10m in the south direction and then turns left and walks 5m to reach her father’s office; then she walks for 8m after taking a right turn and then she takes a right turn and walks 5m.How far is Sania from her initial position?18m22m15m20m
Question
Directions: Sania walks 10m in the south direction and then turns left and walks 5m to reach her father’s office; then she walks for 8m after taking a right turn and then she takes a right turn and walks 5m.How far is Sania from her initial position?18m22m15m20m
Solution
To solve this problem, we need to visualize Sania's movements on a plane.
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Sania starts at a point and walks 10m south. Let's call this point A and her new position point B.
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She then turns left (which would be east if we consider the standard directions) and walks 5m to reach her father's office. Let's call this point C.
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She then takes a right turn (which would be south) and walks 8m. Let's call this point D.
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Finally, she takes another right turn (which would be west) and walks 5m. Let's call this point E.
Now, we need to find the distance between point A (her initial position) and point E (her final position).
If we look at the movements, we can see that the 5m she walked east (from B to C) and the 5m she walked west (from D to E) cancel each other out.
So, the distance from A to E is the same as the distance from A to B plus the distance from C to D.
The distance from A to B is 10m (she walked this distance south), and the distance from C to D is 8m (she walked this distance south).
So, the total distance from A to E is 10m + 8m = 18m.
Therefore, Sania is 18m away from her initial position.
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