The range of positive numbers possible in an 8-bit two's complement system is:
Question
The range of positive numbers possible in an 8-bit two's complement system is:
Solution
In an 8-bit two's complement system, the range of positive numbers is from 1 to 127.
Here's why:
-
An 8-bit system means there are 8 places for binary digits (0s and 1s).
-
In a two's complement system, the leftmost bit (most significant bit) is used to represent the sign of the number: 0 for positive and 1 for negative.
-
Therefore, for positive numbers, the leftmost bit is always 0, leaving 7 bits for the actual number.
-
The maximum number you can represent with 7 bits is 1111111 in binary, which is 127 in decimal.
So, the range of positive numbers in an 8-bit two's complement system is from 1 to 127.
Similar Questions
Suppose that 8-bit two's complement numbers are being employed. What bit pattern corresponds to the decimal integer value −50 (negative fifty):Group of answer choices0011001001001110110011101100110111001111
Subtraction of 60 - 27 in 8-bit Two's Complement Form
What is the range of integers that can be represented using 8 bits and 16 bits in the followingcases:- Unsigned integers.- Signed integers represented with Sign-Magnitude, one’s complement, and two’scomplement.
What does extending to 16 bits yield given -5 in 8-bit 2's complement 11111011?
Why do we use two's complement to represent negative numbers in binary? Choose all that apply. Group of answer choices So that there is only one representation of 0 So that we can perform addition without worrying about the sign of the numbers So that we can use the most significant bit as a sign bit
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.