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Consider this reaction:→2H3PO4aq+P2O5aq3H2OaqAt a certain temperature it obeys this rate law.rate =·1.68M−1s−1H3PO42Suppose a vessel contains H3PO4 at a concentration of 0.850M. Calculate the concentration of H3PO4 in the vessel 4.30 seconds later. You may assume no other reaction is important.Round your answer to 2 significant digits.

Question

Consider this reaction:→2H3PO4aq+P2O5aq3H2OaqAt a certain temperature it obeys this rate law.rate =·1.68M−1s−1H3PO42Suppose a vessel contains H3PO4 at a concentration of 0.850M. Calculate the concentration of H3PO4 in the vessel 4.30 seconds later. You may assume no other reaction is important.Round your answer to 2 significant digits.

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Solution

The given rate law is: rate = k[H3PO4]^2

Where: k = 1.68 M^-1s^-1 (rate constant) [H3PO4] = concentration of H3PO4

The rate of reaction is also given by the change in concentration over the change in time:

rate = -Δ[H3PO4]/Δt

We can set these two expressions for the rate equal to each other and solve for the change in concentration:

-Δ[H3PO4]/Δt = k[H3PO4]^2

Rearranging to solve for Δ[H3PO4] gives:

Δ[H3PO4] = -k[H3PO4]^2 * Δt

Substituting the given values:

Δ[H3PO4] = -(1.68 M^-1s^-1)(0.850 M)^2 * 4.30 s

Calculate the above expression to find the change in concentration. Then subtract this value from the initial concentration to find the final concentration of H3PO4. Round your answer to 2 significant digits.

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