Select the correct answerSuppose list1 is [3, 4, 5, 20, 5, 25, 1, 3], what is list1 after list1.pop(1)?Options[3, 4, 5, 20, 5, 25, 1, 3][3, 5, 20, 5, 25, 1, 3][1, 3, 4, 5, 20, 5, 25][1, 3, 3, 4, 5, 5, 20, 25]
Question
Select the correct answerSuppose list1 is [3, 4, 5, 20, 5, 25, 1, 3], what is list1 after list1.pop(1)?Options[3, 4, 5, 20, 5, 25, 1, 3][3, 5, 20, 5, 25, 1, 3][1, 3, 4, 5, 20, 5, 25][1, 3, 3, 4, 5, 5, 20, 25]
Solution
The correct answer is [3, 5, 20, 5, 25, 1, 3].
Here's the step by step explanation:
- We have the list list1 = [3, 4, 5, 20, 5, 25, 1, 3].
- The pop() function in Python removes and returns the element at the given index. In this case, list1.pop(1) will remove the element at index 1 of list1.
- In Python, indexing starts from 0. So, the element at index 1 in list1 is 4.
- After executing list1.pop(1), the element 4 will be removed from list1.
- Therefore, the list1 after the operation will be [3, 5, 20, 5, 25, 1, 3].
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