Host A wants to send a large file to Host B. The path from Host B has three links, of rates R1 = 500 Kbps, R2 = 2Mbps and a. Assuming no other traffic in the network, what is the throughput for the file transfer.b. Suppose the file is 4 million bytes. Dividing the file size by throughput, roughly how long will it take to transfer the file to Host B?Repeat (a) and (b), but now with R2 reduced to 100kbps.
Question
Host A wants to send a large file to Host B. The path from Host B has three links, of rates R1 = 500 Kbps, R2 = 2Mbps and a. Assuming no other traffic in the network, what is the throughput for the file transfer.b. Suppose the file is 4 million bytes. Dividing the file size by throughput, roughly how long will it take to transfer the file to Host B?Repeat (a) and (b), but now with R2 reduced to 100kbps.
Solution
a. The throughput of a network is determined by the slowest link in the path. In this case, the rates are R1 = 500 Kbps, R2 = 2 Mbps. Therefore, the throughput is 500 Kbps because it is the slowest link.
b. The file size is 4 million bytes. To convert this to bits (since our rate is in bits per second), we multiply by 8 (1 byte = 8 bits), giving us 32 million bits.
The time to transfer can be calculated by dividing the file size by the throughput.
So, 32,000,000 bits / 500,000 bits per second = 64 seconds.
Now, if R2 is reduced to 100 Kbps,
a. The throughput becomes 100 Kbps because it is now the slowest link.
b. Using the same file size, 32,000,000 bits / 100,000 bits per second = 320 seconds.
So, reducing R2 to 100 Kbps increases the time to transfer the file to Host B.
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