Deduce the readings on the ammetersRemember: Current is conserved at a junction: current in = current out0.80A enter the junction, and 0.30A go through resistor P
Question
Deduce the readings on the ammetersRemember: Current is conserved at a junction: current in = current out0.80A enter the junction, and 0.30A go through resistor P
Solution
The current that enters a junction is equal to the current that leaves the junction. This is known as the principle of conservation of charge.
Given that 0.80A of current enters the junction and 0.30A goes through resistor P, we can deduce the reading on the other ammeter(s) by subtracting the current that goes through resistor P from the total current that enters the junction.
So, the calculation would be:
0.80A (total current) - 0.30A (current through resistor P) = 0.50A
Therefore, the reading on the other ammeter(s) should be 0.50A.
Similar Questions
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