elect the correct answerTwo cars A and B travel from one city to another city, at speeds of 60 km/hr and 108 km/hour respectively. If car B takes 2 hours lesser time than car A for the journey, then what is the distance (in km) between the two cities?Options270240300330
Question
elect the correct answerTwo cars A and B travel from one city to another city, at speeds of 60 km/hr and 108 km/hour respectively. If car B takes 2 hours lesser time than car A for the journey, then what is the distance (in km) between the two cities?Options270240300330
Solution
To solve this problem, we need to use the formula for time, which is distance divided by speed.
Let's denote the distance between the two cities as D (in km), the speed of car A as Sa (in km/hr), the speed of car B as Sb (in km/hr), the time taken by car A as Ta (in hrs), and the time taken by car B as Tb (in hrs).
From the problem, we know that:
Sa = 60 km/hr Sb = 108 km/hr Ta = Tb + 2 hrs
We can express the time taken by each car to travel the distance D as follows:
Ta = D/Sa Tb = D/Sb
Substituting the known values into these equations gives us:
D/60 = D/108 + 2
To solve for D, we first need to get rid of the denominators by multiplying each term by 60*108, which gives us:
108D = 60D + 260108
Solving this equation for D gives us:
48D = 260108 D = (260108) / 48 D = 270 km
So, the distance between the two cities is 270 km.
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