The conjugate acid base pair in the following reaction is: CH3COOH + NH3 ⟶ CH3COO− + NH4+ Select an answerA CH3COOH, CH3COO− B CH3COOO−NH4+ C CH3COOH, NH3 D NH3.CH3COO−
Question
The conjugate acid base pair in the following reaction is: CH3COOH + NH3 ⟶ CH3COO− + NH4+ Select an answerA CH3COOH, CH3COO− B CH3COOO−NH4+ C CH3COOH, NH3 D NH3.CH3COO−
Solution
The conjugate acid-base pair in this reaction is A CH3COOH, CH3COO−.
Here's why:
In the reaction, CH3COOH acts as an acid because it donates a proton (H+) to NH3. After donating a proton, CH3COOH becomes its conjugate base CH3COO−.
On the other hand, NH3 acts as a base because it accepts a proton from CH3COOH. After accepting a proton, NH3 becomes its conjugate acid NH4+.
So, the conjugate acid-base pairs are CH3COOH/CH3COO− and NH3/NH4+.
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