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The deflection of a cantilevered beam supporting the weight of an advertising sign is given byy = −Wx26EI(3L − x),where we have the following.y = deflection at a given x location (m)W = weight of the sign (N)E = modulus of elasticity (N/m2)I = second moment of area (m4)x = distance from the support as shown (m)L = length of the beam (m)A vertical brick wall extends upwards from the ground. Near the top of the wall, a cantilever of length L extends rightwards along a horizontal x-axis that begins at the wall. A sign hangs down from the right end of the cantilever.Plot the deflection of a beam with a length of 3 m, the modulus of elasticity of E = 200 GPa, and I = 1.2 ✕ 106 mm4 for a sign weighing 1,500 N. (Submit a file with a maximum size of 1 MB.)

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The deflection of a cantilevered beam supporting the weight of an advertising sign is given byy = −Wx26EI(3L − x),where we have the following.y = deflection at a given x location (m)W = weight of the sign (N)E = modulus of elasticity (N/m2)I = second moment of area (m4)x = distance from the support as shown (m)L = length of the beam (m)A vertical brick wall extends upwards from the ground. Near the top of the wall, a cantilever of length L extends rightwards along a horizontal x-axis that begins at the wall. A sign hangs down from the right end of the cantilever.Plot the deflection of a beam with a length of 3 m, the modulus of elasticity of E = 200 GPa, and I = 1.2 ✕ 106 mm4 for a sign weighing 1,500 N. (Submit a file with a maximum size of 1 MB.)

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