One of the ZEROs of Antisymmetry FIR filter is at 0.5 ∠60. Show locations of otherZEROS. What is the minimum order of this filter?
Question
One of the ZEROs of Antisymmetry FIR filter is at 0.5 ∠60. Show locations of otherZEROS. What is the minimum order of this filter?
Solution
To find the locations of the other zeros of the Antisymmetry FIR filter, we need to consider the properties of the filter.
Since one of the zeros is at 0.5 ∠60, we know that the filter is symmetric about the imaginary axis in the complex plane. This means that the other zeros will also be symmetric about the imaginary axis.
To determine the locations of the other zeros, we can use the conjugate property of complex numbers. The conjugate of a complex number a + bi is given by a - bi.
In this case, the conjugate of 0.5 ∠60 is 0.5 ∠(-60), which is equal to 0.5 ∠-60. Therefore, one of the other zeros is located at 0.5 ∠-60.
Since the filter is symmetric, there will be an equal number of zeros on the left side of the imaginary axis as there are on the right side. Therefore, the minimum order of this filter is 2, as there are two zeros in total.
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