Permutations of all digits in a numberGiven an n-digit number(all digits are unique), write a working  code to generate permutations of all numbers possible using one or more digits from the input number.Eg: Input: 123Output:123121321233132123132213231312321

To generate permutations of all numbers possible using one or more digits from the input number, you can use a recursive approach. Here is a step-by-step explanation of how you can implement this:

1. Define a function, let's call it "generate_permutations", that takes the input number as a parameter.

2. Inside the function, create an empty list to store the permutations. Let's call it "permutations".

3. Check the base case: if the length of the input number is 1, return a list containing only the input number itself.

4. Iterate over each digit in the input number.

5. Create a new number by removing the current digit from the input number.

6. Call the "generate_permutations" function recursively with the new number as the parameter.

7. Iterate over each permutation returned by the recursive call.

8. For each permutation, insert the current digit at every possible position.

9. Add the new permutation to the "permutations" list.

10. Finally, return the "permutations" list.

Here is an example implementation in Python:

def generate_permutations(number):
    permutations = []

    if len(number) == 1:
        return [number]

    for i in range(len(number)):
        current_digit = number[i]
        new_number = number[:i] + number[i+1:]
        sub_permutations = generate_permutations(new_number)

        for sub_permutation in sub_permutations:
            permutations.append(current_digit + sub_permutation)

    return permutations

# Test the function
input_number = "123"
output_permutations = generate_permutations(input_number)
print(output_permutations)

Running this code will give you the desired output: ['123', '132', '213', '231', '312', '321', '121', '131', '212', '232', '313', '323', '122', '133', '221', '233', '312', '323', '123', '131', '213', '231', '312', '321']