In the reaction MgCl2 + 2KOH Mg(OH)2 + 2KCl, if 6 moles MgCl2 are added to 6 moles KOH, which is the limiting reagent?A.KOHB.MgCl2C.KClD.None of the aboveSUBMITarrow_backPREVIOUS
Question
In the reaction MgCl2 + 2KOH Mg(OH)2 + 2KCl, if 6 moles MgCl2 are added to 6 moles KOH, which is the limiting reagent?A.KOHB.MgCl2C.KClD.None of the aboveSUBMITarrow_backPREVIOUS
Solution
The limiting reagent in a chemical reaction is the reactant that is completely consumed first and determines when the reaction stops.
In the given reaction, the stoichiometry (the ratio of reactants to products) is 1 mole of MgCl2 reacts with 2 moles of KOH to produce 1 mole of Mg(OH)2 and 2 moles of KCl.
If we have 6 moles of MgCl2 and 6 moles of KOH, we can see that we do not have enough KOH for all the MgCl2 to react. This is because, according to the stoichiometry of the reaction, we need 2 moles of KOH for every 1 mole of MgCl2. So for 6 moles of MgCl2, we would need 12 moles of KOH. But we only have 6 moles of KOH.
Therefore, KOH is the limiting reagent. So, the answer is A. KOH.
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