Find the sum of 'n' terms of the series 4² +6² +8²​

The given series is a series of squares of even numbers.

The general term of the series can be written as (2n)², where n is the term number.

The sum of squares of first 'n' natural numbers is given by the formula: n/6 * (n+1) * (2n+1)

But in our case, we are dealing with squares of even numbers, so we replace n with 2n in the formula.

So, the sum of squares of first 'n' even numbers is given by: n/6 * (2n+1) * (4n+1)

This is the sum of 'n' terms of the series 4² +6² +8²​.

The given series is a series of squares of even numbers. The general term of this series can be written as (2n)², where n is the term number.

The sum of squares of first 'n' natural numbers is given by the formula: n(n + 1)(2n + 1) / 6

But in our case, we have the series of squares of even numbers, so we replace n with 2n in the above formula.

So, the sum of squares of first 'n' even numbers is given by: 2n(2n + 1)(4n + 1) / 6

This is the sum of 'n' terms of the series 4² +6² +8²​.