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A hand- made projector employs a concave mirror to project an image onto a screen. If an object with a height of 4 cm is positioned 15 cm in front of the concave mirror with focal length 10 cm, at what distance should the screen be located to capture a sharp image and also calculate the height of the image formed on the screen.30 cm and 8 cm respectively30 cm and 6 cm respectively15 cm and 8 cm respectively15 cm and 6 cm respectively

Question

A hand- made projector employs a concave mirror to project an image onto a screen. If an object with a height of 4 cm is positioned 15 cm in front of the concave mirror with focal length 10 cm, at what distance should the screen be located to capture a sharp image and also calculate the height of the image formed on the screen.30 cm and 8 cm respectively30 cm and 6 cm respectively15 cm and 8 cm respectively15 cm and 6 cm respectively

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Solution

To solve this problem, we can use the mirror formula and magnification formula.

The mirror formula is 1/f = 1/v + 1/u, where f is the focal length, v is the image distance, and u is the object distance.

Given that f = 10 cm and u = -15 cm (the negative sign indicates that the object is on the same side of the mirror as the light source), we can substitute these values into the mirror formula to find v:

1/v = 1/f - 1/u 1/v = 1/10 - 1/(-15) 1/v = 1/10 + 1/15 1/v = (3 + 2) / 30 1/v = 5/30 v = 30/5 v = 6 cm

The negative sign indicates that the image is formed on the same side as the light source. Therefore, the screen should be located 6 cm from the mirror.

The magnification formula is m = -v/u = h'/h, where m is the magnification, h' is the height of the image, and h is the height of the object.

Substituting the given and calculated values into the magnification formula, we find:

m = -v/u = h'/h -6/-15 = h'/4 h' = 4 * 6/15 h' = 1.6 cm

Therefore, the height of the image formed on the screen is 1.6 cm.

So, none of the given options are correct. The screen should be located 6 cm from the mirror, and the height of the image formed on the screen is 1.6 cm.

This problem has been solved

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