To solve this problem, we need to use the combination formula, which is used when the order of selection does not matter. The formula is:

C(n, k) = n! / [k!(n-k)!]

Where:
- n is the total number of items (in this case, 15 executives)
- k is the number of items to choose (in this case, 4 executives)
- "!" denotes a factorial, meaning the product of all positive integers up to that number.

Substituting these into the formula gives:

C(15, 4) = 15! / [4!(15-4)!] = (15*14*13*12) / (4*3*2*1) = 1365

So there are 1365 different ways to select four executives from a group of 15 executives.

Question

To solve this problem, we need to use the combination formula, which is used when the order of selection does not matter. The formula is:

C(n, k) = n! / [k!(n-k)!]

Where:
- n is the total number of items (in this case, 15 executives)
- k is the number of items to choose (in this case, 4 executives)
- "!" denotes a factorial, meaning the product of all positive integers up to that number.

Substituting these into the formula gives:

C(15, 4) = 15! / [4!(15-4)!] = (15*14*13*12) / (4*3*2*1) = 1365

So there are 1365 different ways to select four executives from a group of 15 executives.

Knowee AI · Accepted Answer

To solve this problem, we need to use the combination formula, which is used when the order of selection does not matter. The formula is:

C(n, k) = n! / [k!(n-k)!]

Where:
- n is the total number of items (in this case, 15 executives)
- k is the number of items to choose (in this case, 4 executives)
- "!" denotes a factorial, meaning the product of all positive integers up to that number.

Substituting these into the formula gives:

C(15, 4) = 15! / [4!(15-4)!] = (15*14*13*12) / (4*3*2*1) = 1365

So there are 1365 different ways to select four executives from a group of 15 executives.

Select four executives from 15 executives to participate in this year's summary meeting. How many choices are there?

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