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Assume that d is a Python dictionary. What does the following Python code produce?result = dict()for key in d:    val = d[key]    if val not in result:        result[val] = [key]    else:        result[val].append(key)Question 7Select one:a.a histogramb.an inverted dictionaryc.a list of tuplesd.a lookupe.a reverse lookup

Question

Assume that d is a Python dictionary. What does the following Python code produce?result = dict()for key in d:    val = d[key]    if val not in result:        result[val] = [key]    else:        result[val].append(key)Question 7Select one:a.a histogramb.an inverted dictionaryc.a list of tuplesd.a lookupe.a reverse lookup

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Solution

The given Python code produces an inverted dictionary.

Here's how it works:

  1. It first creates an empty dictionary named 'result'.
  2. Then it iterates over each key in the dictionary 'd'.
  3. For each key, it gets the corresponding value from 'd'.
  4. It then checks if this value is already a key in the 'result' dictionary.
  5. If the value is not already a key in 'result', it adds the value as a key to 'result' with the corresponding value being a list containing the current key from 'd'.
  6. If the value is already a key in 'result', it appends the current key from 'd' to the list of values for this key in 'result'.

So, the correct answer is b. an inverted dictionary.

This problem has been solved

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