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A watch was sold at a discount of 12% of its usual price. During a flash sale, Eric bought the watch with an additional 5% discount on the discounted price. He paid $209. What was the usual price of the watch?​

Question

A watch was sold at a discount of 12% of its usual price. During a flash sale, Eric bought the watch with an additional 5% discount on the discounted price. He paid $209. What was the usual price of the watch?​

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Solution

Sure, let's solve this step by step:

Step 1: First, we need to understand that Eric got two discounts on the watch. The first discount was 12% off the usual price, and the second discount was an additional 5% off the already discounted price.

Step 2: Let's denote the usual price of the watch as X.

Step 3: After the first discount of 12%, the price of the watch became 88% of the usual price. So, we can write this as 0.88X.

Step 4: During the flash sale, Eric got an additional 5% discount on the discounted price. So, the price of the watch after the second discount is 95% of the discounted price, which we can write as 0.95 * 0.88X.

Step 5: We know that Eric paid 209forthewatchafterbothdiscounts.So,wecansetuptheequation0.950.88X=209 for the watch after both discounts. So, we can set up the equation 0.95 * 0.88X = 209.

Step 6: To find the usual price X, we need to solve this equation for X. We can do this by dividing both sides of the equation by 0.95 * 0.88.

So, X = 209/(0.950.88)=209 / (0.95 * 0.88) = 250.

Therefore, the usual price of the watch was $250.

This problem has been solved

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