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What is the time complexity of searching for an element in a queue of size n if you are given a pointer to both the head and the tail of the queue?O(n)O(1)O(log(n))O(nlog(n))O(2^n)O(n!)O(n^2)

Question

What is the time complexity of searching for an element in a queue of size n if you are given a pointer to both the head and the tail of the queue?O(n)O(1)O(log(n))O(nlog(n))O(2^n)O(n!)O(n^2)

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Solution

The time complexity of searching for an element in a queue of size n, even if you are given a pointer to both the head and the tail of the queue, is O(n). This is because you may potentially have to look at every element in the queue in the worst-case scenario. The pointers to the head and tail do not help in the search operation, they only help in enqueue and dequeue operations.

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What is the time complexity of “pushing” an element into a queue if you are given a pointer to both the head and the tail of the queue?O(n!)O(2^n)O(1)O(n)O(nlog(n))O(n^2)O(log(n))

What is the time complexity of searching for an element in a stack of size n?O(n!)O(2^n)O(1)O(n)O(nlog(n))O(n^2)O(log(n))

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What is the time complexity of searching for an element in a singly linked list of size n?O(n!)O(2^n)O(1)O(n)O(nlog(n))O(n^2)O(log(n))

What is the time complexity of “popping” an element in a queue if you are given a pointer to both the head and the tail of the queue?

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