The average monthly income of P and Q is Rs .8690. The average monthly income of Q and R is RS. 11120 and that of P and R is RS. 9850. What is the monthly income of P?OptionsRS.7000RS.74207360RS.7620RS.8840

To solve this problem, we can use the method of simultaneous equations.

Given:

1. The average monthly income of P and Q is Rs. 8690. So, P + Q = 8690 * 2 = 17380
2. The average monthly income of Q and R is Rs. 11120. So, Q + R = 11120 * 2 = 22240
3. The average monthly income of P and R is Rs. 9850. So, P + R = 9850 * 2 = 19700

Now, we can add the first and second equations and subtract the third equation from the result to find the monthly income of P.

(P + Q) + (Q + R) - (P + R) = 17380 + 22240 - 19700

Solving this gives us:

2Q = 19920

So, Q = 19920 / 2 = Rs. 9960

Substituting the value of Q in the first equation, we get:

P + 9960 = 17380

So, P = 17380 - 9960 = Rs. 7420

Therefore, the monthly income of P is Rs. 7420.

To solve this problem, we can use the method of simultaneous equations.

Given:

1. The average monthly income of P and Q is Rs. 8690. So, P + Q = 8690 * 2 = 17380
2. The average monthly income of Q and R is Rs. 11120. So, Q + R = 11120 * 2 = 22240
3. The average monthly income of P and R is Rs. 9850. So, P + R = 9850 * 2 = 19700

Now, we can add the first and second equations and subtract the third equation from the result to find the monthly income of P.

(P + Q) + (Q + R) - (P + R) = 17380 + 22240 - 19700

Solving this gives: Q = 19920

Substitute Q = 19920 in the first equation (P + Q = 17380), we get:

P = 17380 - 19920 = -2540

This is not a valid answer as income cannot be negative. There seems to be a mistake in the problem. The given options do not match the calculated result. Please check the problem again.