You are given a year in the form of an integer 'N', and your task is to check whether the given year is a leap year or not.Note:1) A year is said to be a leap year if it has 366 days. Normal years have 365 days.2) The integer 'N' does not contain any leading zeros.Sample Input 1:220002020Sample Output 1:YesYesExplanation for Sample Output 1:In test case 1, The year 2000 had 366 days since there were 29 days in the month of February in the year 2000.
Question
You are given a year in the form of an integer 'N', and your task is to check whether the given year is a leap year or not.Note:1) A year is said to be a leap year if it has 366 days. Normal years have 365 days.2) The integer 'N' does not contain any leading zeros.Sample Input 1:220002020Sample Output 1:YesYesExplanation for Sample Output 1:In test case 1, The year 2000 had 366 days since there were 29 days in the month of February in the year 2000.
Solution
To determine whether a year is a leap year or not, you can follow these steps:
- First, check if the year is divisible by 4. If it is not, then it is a normal year.
- If the year is divisible by 4, then check if it is divisible by 100. If it is not, then it is a leap year.
- If the year is divisible by 100, then check if it is also divisible by 400. If it is, then it is a leap year. If it is not, then it is a normal year.
Here is a Python code snippet that implements these steps:
def is_leap_year(year):
if year % 4 != 0:
return "No"
elif year % 100 != 0:
return "Yes"
elif year % 400 != 0:
return "No"
else:
return "Yes"
You can use this function to check if a year is a leap year or not. For example, is_leap_year(2000) returns "Yes" and is_leap_year(2020) also returns "Yes". This is because both 2000 and 2020 are divisible by 4, and 2000 is also divisible by 400.
Similar Questions
Given a year, determine whether it is a leap year. If it is a leap year, return the Boolean True, otherwise return False.Note that the code stub provided reads from STDIN and passes arguments to the is_leap function. It is only necessary to complete the is_leap function.
Single File Programming QuestionProblem StatementMerlin is working on a calendar application that requires a leap-year verification feature for accurate event scheduling. Users input a year, and her program determines whether it's a leap year or not, aiding in precise calendar calculations. Help her write a program to determine if the given year is a leap year or not by using only switch statements and operators.Note: This question was asked in TCS coding test.Input format :The input consists of an integer representing the year.Output format :If the given year is a leap year, the output prints "<<Input year>> is a leap year."Otherwise, the output prints "<<Input year>> is not a leap year."Refer to the sample output for the formatting specifications.Code constraints :In this scenario, the test cases fall under the following constraints:1900 ≤ Input year ≤ 2100
The algorithm below determines whether a given year is a leap year.If year is not divisible by 4, set leap_year to falseElse if year is not divisible by 100, set leap_year to trueElse if year is not divisible by 400, set leap_year to falseElse, set leap_year to true.Which of these tables correctly shows the results of this algorithm on the given values of year?Choose 1 answer:Choose 1 answer:(Choice A) year leap_year1900 false1984 true2000 false2002 falseAyear leap_year1900 false1984 true2000 false2002 false(Choice B) year leap_year1900 false1984 true2000 true2002 falseByear leap_year1900 false1984 true2000 true2002 false(Choice C) year leap_year1900 true1984 true2000 false2002 falseCyear leap_year1900 true1984 true2000 false2002 false(Choice D) year leap_year1900 true1984 true2000 true2002 falseDyear leap_year1900 true1984 true2000 true2002 false
Create a class Year to read year and find whether is is leap year or not. Create a class month which display 12 months . Create a class import which uses above classes and tell the current month and year and also tell whether it is leap or not
Search course Type to search Minimum 3 characters required for search Close 1.1.2. Leap year checking 02:30 Sophia, a software developer, is working on a calendar application where accurate identification of leap years is crucial. She needs a program that efficiently checks whether a given year is a leap year. In the Gregorian calendar, a leap year is either divisible by 4 but not divisible by 100, or it is divisible by 400. Write a Java program that takes a year as input and uses a ternary operator to determine and display whether the provided year is a leap year or not. Input format: The input is the integer that represents the year. Output format: The output states whether the given year is leap year or not as shown in displayed test cases. Note: The code for handling inputs and outputs is already been given, your task is to fill in the required code. Sample Test Cases Explorer LeapYearChecker.java Submit 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 ⌄ ⌄ package q22489; import java.util.Scanner; public class LeapYearChecker { public static void main(String[] args) { Scanner scanner = new Scanner(System.in); int year = scanner.nextInt(); String result = (year%==0)?"Leap year": "Not a leap year"; System.out.println(year + " is " + result); scanner.close(); } } Terminal Test cases Reason for late submission Eucs.Learner.Contents.LateSubmissionModal.Input.Placeholder Please enter at least 15 characters
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