A university newspaper claims that 46% of college students at that university have a job outside of the university. A statistics professor thinks that the actual number is less than this. She asks her students to conduct a survey with a random sample of 200 students. According to their results, 82 of the surveyed students have a job outside of the university. They calculated the test statistics: z = -1.42.Using 5% significance level, do they have enough evidence to reject the newspapers claim?

In 2017, 20.1% of all high school students in the U.S. had a job. A school official from a district thought that the percentage of high school students who had a job in that school district was higher than the national proportion. She took a random sample of 285 high school students and found that 64 of had a job.Is this survey valid or not valid for testing the hypothesis that the proportion of the high school students who worked in that district is higher than the national average?

The National Institute of Mental Health published an article stating that in any one-year period, approximately 9.8% of American adults suffer from depression or a depressive illness. Suppose that in a survey of 2000 people in a certain city, 10.4% of them suffered from depression or a depressive illness. Conduct a hypothesis test to determine if the true proportion of people in that city suffering from depression or a depressive illness is more than the 9.8% in the general adult American population. Test the relevant hypotheses using a 5% level of significance. Give answer to at least 4 decimal places.a. What are the correct hypotheses? (Select the correct symbols and use decimal values not percentages.)H0: H1:  b. Based on the hypotheses, find the following:c. Test Statistic =  d. p-value =    e. Based on the above we choose to f. The correct summary would be: that the true proportion of people in that city suffering from depression or a depressive illness is more than the percent in the general adult American population of 9.8%.

According to a U.S. news poll, 38% of students in the class of 2013 had done an internship during their time as an undergraduate student. Dana is interested in finding out whether students at her university had an internship rate that was higher than the national average. She obtained a list of 25 randomly selected students from the population of all students at her university by requesting this information from the university’s institutional research office. She collected the responses and calculated that the proportion for her university was 43%.Which one of the following statements about the z-test is correct? It is not safe to use the z-test for p, since n * po is not large enough. It is safe to use the z-test for p. It is not safe to use the z-test for p, since the sample is not a random sample from the entire population (or cannot be considered as one). It is not safe to use the z-test for p, since n * (1 − po) is not large enough.

According to Facebook’s self-reported statistics, the average Facebook user is connected to 80 community pages, groups, and events. For a statistics project, a student at Contra Costa College tests the hypothesis that CCC students will average less than 80 such connections.She posts a survey on her Facebook page. Her sample contains 45 responses.She chooses a 5% level of significance. From her data she calculates a t-test statistic of approximately −1.74 with a P-value of about 0.04.What can she conclude? The data is not statistically significant. In other words, the data do not provide enough evidence to conclude that the mean number of Facebook connections to community pages, groups and events of all CCC college students is less the 80. Nothing. The conditions for use of a t-test are not met. She cannot trust that the P-value is accurate for this reason. The data is statistically significant. In other words, the data do provide enough evidence to conclude that the mean number of Facebook connections to community pages, groups and events of all all CCC college students is less the 80.

Time magazine reported the result of a telephone poll of 800 adult Americans. The question posed of the Americans who were surveyed was: "Should the federal tax on cigarettes be raised to pay for health care reform?" The question to be investigated: Is there sufficient evidence at the 𝛼=0.05, say, to conclude that the two populations — smokers and non-smokers — differ significantly with respect to their opinions?The test statistic for this hypothesis test is z = 2.18 with p-value 0.0292.What is the correct conclusion?