The total number of lines obtained in the emission spectrum when electrons in a sample of hydrogen atoms de-excites from the 4th excited state without any transition to the 3rd orbit.

In a hydrogen atom, a transition from the 2nd to the 1st excited state will produceGroup of answer choicesan ultraviolet spectral line.no emission line.the Balmer series line in visible light..three different emission lines.a dark absorption line.

A hydrogen spectrum is observed using a hydrogen lamp, an emission line with a wavelength of 398 nm is associated with excited electrons dropping down to the n = 2 shell. The initial n value for this transition is [Ans].

identify the difference between the emission line Spectrum and the absorption lines spectrum of hydrogen

The energy E of the electron in a hydrogen atom can be calculated from the Bohr formula:=E−Ryn2In this equation Ry stands for the Rydberg energy, and n stands for the principal quantum number of the orbital that holds the electron. (You can find the value of the Rydberg energy using the Data button on the ALEKS toolbar.)Calculate the wavelength of the line in the emission line spectrum of hydrogen caused by the transition of the electron from an orbital with =n5 to an orbital with =n3. Round your answer to 3 significant digits.μm

In a H-like sample, electrons make transition from 4th excited state up to 2nd state. Then