The ratio of Aiden to Daniel's savings was 4 : 5 at first. After Aiden saved another $138 and Daniel saved another $39, Aiden had twice of Daniel's amount. How much did Aiden have in the end?
Question
The ratio of Aiden to Daniel's savings was 4 : 5 at first. After Aiden saved another 39, Aiden had twice of Daniel's amount. How much did Aiden have in the end?
Solution
Let's solve this step by step:
Step 1: Let's assume the initial savings of Aiden and Daniel are 4x and 5x respectively.
Step 2: According to the problem, Aiden saved another 39. So, the new savings of Aiden and Daniel are 4x + 39 respectively.
Step 3: The problem also states that after saving the additional money, Aiden had twice of Daniel's amount. So, we can set up the following equation: 4x + 39)
Step 4: Simplify the equation: 4x + 78
Step 5: Rearrange the equation to find the value of x: 6x = 10
Step 6: Substitute x = 138 = 4*138 = $178
So, Aiden had $178 in the end.
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