In a rectangular park with dimensions 250 m x 150 m, a 2.5 m wide path all around inside it is to be constructed. Also 2 m wide paths are to be constructed in the centre of the park parallel to its length and the other parallel to its breadth. Find the cost (in) of constructing the paths at ₹80 per sq.m.221680221690221610221780

The first step is to calculate the area of the path around the park. The outer dimensions of the park are 250m x 150m, and the path is 2.5m wide on both sides. So, the inner dimensions of the park (inside the path) are (250-2.52) m x (150-2.52) m = 245m x 145m.

The area of the path around the park is the difference between the outer area and the inner area. That is (250150) - (245145) = 3750 sq.m.

Next, we calculate the area of the paths in the centre of the park. One path is parallel to the length (250m) and 2m wide, so its area is 2502 = 500 sq.m. The other path is parallel to the breadth (150m) and 2m wide, so its area is 1502 = 300 sq.m.

However, the intersection of the two paths in the centre is counted twice, so we subtract the area of the intersection, which is 2m x 2m = 4 sq.m.

So, the total area of the paths in the centre of the park is 500 + 300 - 4 = 796 sq.m.

The total area of all the paths is 3750 + 796 = 4546 sq.m.

Finally, the cost of constructing the paths is the area times the cost per square meter, which is 4546 * ₹80 = ₹363,680.