To solve this problem, we need to follow these steps:

1. Read the value of N, the number of students, from the input.
2. Create an empty list called "records" to store the names and grades of each student.
3. Use a loop to iterate N times and perform the following steps for each student:
a. Read the name of the student from the input and store it in a variable called "name".
b. Read the grade of the student from the input and store it in a variable called "grade".
c. Create a nested list with the student's name and grade, and append it to the "records" list.
4. Sort the "records" list based on the grades of the students in ascending order.
5. Find the second lowest grade by iterating through the "records" list and comparing each grade with the previous one. Store the second lowest grade in a variable called "second_lowest_grade".
6. Create an empty list called "second_lowest_students" to store the names of the students with the second lowest grade.
7. Iterate through the "records" list again and for each student, if their grade is equal to the "second_lowest_grade", append their name to the "second_lowest_students" list.
8. Sort the "second_lowest_students" list alphabetically.
9. Print each name in the "second_lowest_students" list on a new line.

Here is the code that implements the above steps:

```python
N = int(input())

records = []
for _ in range(N):
name = input()
grade = float(input())
records.append([name, grade])

records.sort(key=lambda x: x[1])

second_lowest_grade = None
for i in range(1, N):
if records[i][1] records[i-1][1]:
second_lowest_grade = records[i][1]
break

second_lowest_students = []
for record in records:
if record[1] == second_lowest_grade:
second_lowest_students.append(record[0])

second_lowest_students.sort()

for student in second_lowest_students:
print(student)
```

This code will read the input, store the records, find the second lowest grade, and print the names of the students with the second lowest grade in alphabetical order.

Question

To solve this problem, we need to follow these steps:

1. Read the value of N, the number of students, from the input.
2. Create an empty list called "records" to store the names and grades of each student.
3. Use a loop to iterate N times and perform the following steps for each student:
   a. Read the name of the student from the input and store it in a variable called "name".
   b. Read the grade of the student from the input and store it in a variable called "grade".
   c. Create a nested list with the student's name and grade, and append it to the "records" list.
4. Sort the "records" list based on the grades of the students in ascending order.
5. Find the second lowest grade by iterating through the "records" list and comparing each grade with the previous one. Store the second lowest grade in a variable called "second_lowest_grade".
6. Create an empty list called "second_lowest_students" to store the names of the students with the second lowest grade.
7. Iterate through the "records" list again and for each student, if their grade is equal to the "second_lowest_grade", append their name to the "second_lowest_students" list.
8. Sort the "second_lowest_students" list alphabetically.
9. Print each name in the "second_lowest_students" list on a new line.

Here is the code that implements the above steps:

```python
N = int(input())

records = []
for _ in range(N):
    name = input()
    grade = float(input())
    records.append([name, grade])

records.sort(key=lambda x: x[1])

second_lowest_grade = None
for i in range(1, N):
    if records[i][1] > records[i-1][1]:
        second_lowest_grade = records[i][1]
        break

second_lowest_students = []
for record in records:
    if record[1] == second_lowest_grade:
        second_lowest_students.append(record[0])

second_lowest_students.sort()

for student in second_lowest_students:
    print(student)
```

This code will read the input, store the records, find the second lowest grade, and print the names of the students with the second lowest grade in alphabetical order.

Knowee AI · Accepted Answer

To solve this problem, we need to follow these steps:

1. Read the value of N, the number of students, from the input.
2. Create an empty list called "records" to store the names and grades of each student.
3. Use a loop to iterate N times and perform the following steps for each student:
   a. Read the name of the student from the input and store it in a variable called "name".
   b. Read the grade of the student from the input and store it in a variable called "grade".
   c. Create a nested list with the student's name and grade, and append it to the "records" list.
4. Sort the "records" list based on the grades of the students in ascending order.
5. Find the second lowest grade by iterating through the "records" list and comparing each grade with the previous one. Store the second lowest grade in a variable called "second_lowest_grade".
6. Create an empty list called "second_lowest_students" to store the names of the students with the second lowest grade.
7. Iterate through the "records" list again and for each student, if their grade is equal to the "second_lowest_grade", append their name to the "second_lowest_students" list.
8. Sort the "second_lowest_students" list alphabetically.
9. Print each name in the "second_lowest_students" list on a new line.

Here is the code that implements the above steps:

```python
N = int(input())

records = []
for _ in range(N):
    name = input()
    grade = float(input())
    records.append([name, grade])

records.sort(key=lambda x: x[1])

second_lowest_grade = None
for i in range(1, N):
    if records[i][1] > records[i-1][1]:
        second_lowest_grade = records[i][1]
        break

second_lowest_students = []
for record in records:
    if record[1] == second_lowest_grade:
        second_lowest_students.append(record[0])

second_lowest_students.sort()

for student in second_lowest_students:
    print(student)
```

This code will read the input, store the records, find the second lowest grade, and print the names of the students with the second lowest grade in alphabetical order.

Question

Solution

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