What would be the result of the following code?import java.util.ArrayList;public class ArrayListQuestion { public static void main(String[] args) { ArrayList<String> colors1 = new ArrayList<>(); colors1.add("red"); colors1.add("green"); colors1.add("blue"); colors1.add("yellow"); ArrayList<String> colors2 = new ArrayList<>(colors1); colors2.add("orange"); colors2.add("purple"); colors2.add("pink"); System.out.println(colors2.get(5)); }} a. It will print "purple" b. It will print "pink" c. It will print "green" d. It will throw an exception
Question
What would be the result of the following code?import java.util.ArrayList;public class ArrayListQuestion { public static void main(String[] args) { ArrayList<String> colors1 = new ArrayList<>(); colors1.add("red"); colors1.add("green"); colors1.add("blue"); colors1.add("yellow"); ArrayList<String> colors2 = new ArrayList<>(colors1); colors2.add("orange"); colors2.add("purple"); colors2.add("pink"); System.out.println(colors2.get(5)); }} a. It will print "purple" b. It will print "pink" c. It will print "green" d. It will throw an exception
Solution
The correct answer is a. It will print "purple".
Here's the step by step explanation:
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An ArrayList named colors1 is created and four colors ("red", "green", "blue", "yellow") are added to it.
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Another ArrayList named colors2 is created and it is initialized with the elements of colors1. So, at this point, colors2 also contains the same four colors as colors1.
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Three more colors ("orange", "purple", "pink") are added to colors2. Now, colors2 contains seven colors.
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The code then prints the color at index 5 of colors2. In Java, ArrayList indices start at 0, so the color at index 5 is the sixth color in the list, which is "purple". Therefore, "purple" will be printed.
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