A train can travel 50% faster than a car. Both start from point A at the same time and reach point B 75 kms away from A at the same time. On the way, however, the train lost about 12.5 minutes while stopping at the stations. The speed of the car is:100 kmph110 kmph120 kmph130 kmph
Question
A train can travel 50% faster than a car. Both start from point A at the same time and reach point B 75 kms away from A at the same time. On the way, however, the train lost about 12.5 minutes while stopping at the stations. The speed of the car is:100 kmph110 kmph120 kmph130 kmph
Solution
The problem can be solved by following these steps:
- Let's assume the speed of the car is x kmph.
- Since the train travels 50% faster than the car, the speed of the train is 1.5x kmph.
- The distance from point A to point B is 75 km for both the car and the train.
- The time taken by the car to travel this distance is 75/x hours.
- The train also takes the same time to travel from A to B, but it loses 12.5 minutes (or 12.5/60 hours) due to stops at stations. So, the time taken by the train is 75/1.5x + 12.5/60 hours.
- Since both the car and the train reach point B at the same time, the time taken by them is equal. Therefore, we can equate the two times and solve for x:
75/x = 75/1.5x + 12.5/60
Solving this equation gives x = 100 kmph. So, the speed of the car is 100 kmph.
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