A tank is full of water. Find the work W required to pump the water out of the spout. (Use 9.8 m/s2 for g. Use 1000 kg/m3 as the weight density of water.)4 m4 m6 m3 mA water tank shaped like a triangular prism is given. The base of the prism is at the top and a spout is located at the top of the tank. The dimensions of the tank are 6 meters long, 4 meters wide, and 4 meters deep. The spout is 3 meters long.W = J

To find the work required to pump the water out of the spout, we need to calculate the volume of the water in the tank, the weight of the water, and the distance the water needs to be moved.

1. First, calculate the volume of the water in the tank. The tank is shaped like a triangular prism, so the volume V is given by the formula V = 1/2 * base * height * length. In this case, the base is 4 meters, the height is 4 meters, and the length is 6 meters. So, the volume is V = 1/2 * 4 m * 4 m * 6 m = 48 cubic meters.

2. Next, calculate the weight of the water. The weight density of water is given as 1000 kg/m^3, and weight is density times volume. So, the weight of the water is 1000 kg/m^3 * 48 m^3 = 48000 kg.

3. The work W required to move the water is given by the formula W = weight * g * height, where g is the acceleration due to gravity (9.8 m/s^2) and height is the distance the water needs to be moved. The spout is 3 meters long, but the water also needs to be moved the depth of the tank, which is 4 meters. So, the total height is 3 m + 4 m = 7 m.

4. So, the work required is W = 48000 kg * 9.8 m/s^2 * 7 m = 32928000 Joules.