n how many ways can 5 different books be arranged on a shelf if two particular books must always be together?Choices:- 48 96 120 240
Question
n how many ways can 5 different books be arranged on a shelf if two particular books must always be together?Choices:- 48 96 120 240
Solution
To solve this problem, we can use the concept of permutations in combinatorics.
Step 1: Consider the two books that must always be together as one item. So now we have 4 items in total - the 3 individual books and 1 pair of books.
Step 2: These 4 items can be arranged in 4! (4 factorial) ways. 4 factorial means 432*1 = 24.
Step 3: However, within the pair of books, the two books can be arranged in 2! (2 factorial) ways. 2 factorial means 2*1 = 2.
Step 4: Therefore, the total number of ways the books can be arranged is 4! * 2! = 24 * 2 = 48.
So, the answer is 48.
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